MCQ
Carbolic acid is
- A${C_6}{H_5}CHO$
- B${C_6}{H_6}$
- C${C_6}{H_5}COOH$
- ✓${C_6}{H_5}OH$
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$C{H_3}C{H_2}OH\xrightarrow{{P + {I_2}}}A\xrightarrow[{Ether}]{{Mg}}B $ $\xrightarrow{{HCHO}}C\xrightarrow{{{H_2}O}}D,$
then compound $'D'$ is -
