MCQ
Carbon has zero oxidation number in
- A$CO$
- B$C{H_4}$
- ✓$C{H_2}C{l_2}$
- D$C{H_3}Cl$
$x + 2 - 2 = 0$; $x = 0\,\,in\,\,C{H_2}C{l_2}$.
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$C{H_3}C{H_2}C{H_2}OH \xrightarrow{PCl_3}A\xrightarrow{Alco.KOH}B$