MCQ
Carbon is in the lowest oxidation state in
- ✓$C{H_4}$
- B$CC{l_4}$
- C$C{F_4}$
- D$C{O_2}$
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Major product of above reaction is
$3 HC \equiv CH _{( g )} \rightleftharpoons C _{6} H _{6(\ell)}$
[Given: $\Delta_{f} G ^{\circ}( HC \equiv CH )=-2.04 \times 10^{5}\, J mol ^{-1}$
$\Delta_{f} G ^{\circ}\left( C _{6} H _{6}\right)=-1.24 \times 10^{5}\, J mol ^{-1} ; R =8.314\,\left. J K ^{-1} mol ^{-1}\right]$

