MCQ
Carbyl-amine reaction is given by
- ✓
- B
- C
- D
✓
Answer
Correct option: A.
a
Only primary amine give carbyl-amine reaction.
Only primary amine give carbyl-amine reaction.
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A flask is filled with equal moles of $A$ and $B$. The half lives of $A$ and $B$ are $100\, s$ and $50 \,s$ respectively and are independent of the initial concentration. The time required for the concentration of $A$ to be four times that of $B$ is $....\,s.$
→(Given : $\ln 2=0.693$ )
$\begin{matrix}
O\,\,\, \\
||\,\,\, \\
C{{H}_{3}}-C-C{{H}_{2}}- \\
\end{matrix}\begin{matrix}
O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
C{{H}_{2}}-C-C{{H}_{3}}\xrightarrow[\Delta ]{{{(N{{H}_{4}})}_{2}}C{{O}_{3}}}\xrightarrow[\Delta ]{CC{{l}_{3}}C{{O}_{2}}Na}\underset{(major)}{\mathop{(B)}}\, \\
\end{matrix}$
→O\,\,\, \\
||\,\,\, \\
C{{H}_{3}}-C-C{{H}_{2}}- \\
\end{matrix}\begin{matrix}
O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
C{{H}_{2}}-C-C{{H}_{3}}\xrightarrow[\Delta ]{{{(N{{H}_{4}})}_{2}}C{{O}_{3}}}\xrightarrow[\Delta ]{CC{{l}_{3}}C{{O}_{2}}Na}\underset{(major)}{\mathop{(B)}}\, \\
\end{matrix}$
Product $(B)$ of above reaction is