MCQ
$Ce - 58$ is a member of
- A$s$-block elements
- B$p$-block elements
- C$d$-block elements
- ✓$f$-block elements
Since the electron has entered the $f$ orbital, $Ce$ is an $f$ block element.
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Reason : The carbon atom carrying negative charge has an octet of electrons.

$C{H_3}COOH\xrightarrow{{LiAl{H_4}}}A\mathop {\xrightarrow{{{H^ + }}}}\limits_{443\,K} B\xrightarrow{{B{r_2}}}C\mathop {\xrightarrow{{alc.}}}\limits_{KOH} D$