MCQ
$CH _3 CHO$ and $C _6 H _5 CH _2 CHO$ can be distinguished chemically by :
- ABenedict test
- ✓Iodoform test
- CTollens' reagent test
- DFehling solution test
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$C{H_3}C{H_2}COOH\xrightarrow{{SOC{l_2}}}\,B\,$$ \xrightarrow{{N{H_3}}}\,C\,\xrightarrow[{B{r_2}}]{{KOH}}\,D$
The structure of $D$ would be

|
List-$I$ (Complexion) |
List-$II$ (Spin only magnetic moment in B.M.) |
| $A$ ${\left[\mathrm{Cr}\left(\mathrm{NH}_5\right)_0\right]^{3+}}$ | $I$ $4.90$ |
| $B$ ${\left[\mathrm{NiCl}_4\right]^{2-}}$ | $II$ $3.87$ |
| $C$ ${\left[\mathrm{CoF}_6\right]^{3-}}$ | $III$ $0.0$ |
| $D$ ${\left[\mathrm{Ni}(\mathrm{CN})_4\right]^{2-}}$ | $IV$ $2.83$ |
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