MCQ
$C{H_3} - CH = CH - C{H_3}\xrightarrow[{(ii){H_2}O,Zn}]{{(i){O_3}}}{\text{Product}}$
- A$CH_3-CH_2-CHO$
- ✓$CH_3-CHO$
- C$CH_3-COOH$
- D$\begin{array}{*{20}{c}}
{C{H_3} - C = O} \\
{\,\,\,\,|} \\
{\,\,\,\,\,\,\,\,\,C{H_3}}
\end{array}$
✓
Answer
Correct option: B.
$CH_3-CHO$
b
Hence option $C$ is correct.
Hence option $C$ is correct.
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