Question
- $\text{CH}_{3}-\text{CH}_{2}-\text{ Br}\xrightarrow{\text{AgCN } } ?$
✓
Answer
- $\ce{CH_3CH_2NC}.$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
An organic compound ‘$A’ \ce{(C_3H_4)}$ on hydration in presence of $\ce{H_2SO_4/ HgSO_4}$ gives compound ‘$B’ \ce{(C_3H_6O)}$. Compound ‘$B’$ gives white crystalline product $(D)$ with sodium hydrogensulphite. It gives negative Tollens’ test and positive iodoform’s test. On drastic oxidation $‘B\ ’$ gives compound $'C\ ’ \ce{(C_2H_4O_2)}$ along with formic acid. Identify compounds $'A\ ’, 'B\ ’$ and $'C\ ’$ and explain all the reactions.
→Consider a certain reaction A → Products with k = 2 × 10-2 s-1. Calculate the concentration of A remaining after 100 s if the initial concnetration of A is 1.0 mol L-1.
The rate of a particular reaction triples when temperature changes from $50^\circ C$ to $100^\circ C$. Calculate the activation energy of the reaction.$[\log 3 = 0.4771; R = 8.314 \ JK^{-1} \ mol^{-1}].$
→Predict the order of reactivity of the following compounds in $S_N1$ and $S_N2$ reactions: $\ce{C_6H_5CH_2Br, C_6H_5CH(C_6H_5)Br, C_6H_5CH(CH_3)Br, C_6H_5C(CH_3)(C_6H_5)Br}.$
→A solution prepared by dissolving $1.25g$ of oil of winter green $($methyl salicylate$)$ in $99.0g$ of benzene has a boiling point of $80.31^\circ C.$ Determine the molar mass of this compound. $(B.P.$ of pure benzene $= 80.10^\circ C$ and $Kb$ for benzene $= 2.53^\circ C \ kg\ mol^{–1}).$
→Calculate the molarity of 250 mL solution made by dissolving 5 g NaOH in water.
Explain how does -OH group attached to a carbon of benzene ring activate towards electrophilic substitution?
The decomposition of A into product has value of k as $4.5\times10^{3}s^{-1}$ at $10^{\circ}C$ and energy of activation $60~kJ~mol^{-1}$. At what temperature would k be $1.5\times10^{10}s^{-1}$?
→Estimate the minimum potential difference needed to reduce $Al_2O_3 at 500^\circ C$. The free energy change for the decomposition reaction,
$\frac{2}{3}\text{Al}_2\text{O}_3\frac{4}{3}\text{Al + O}_2\text{ is }960\text{kJ (F = 96500C mol}-1)$
→$\frac{2}{3}\text{Al}_2\text{O}_3\frac{4}{3}\text{Al + O}_2\text{ is }960\text{kJ (F = 96500C mol}-1)$
Write the major monohalo product(s) in each of the following reactions :
