- ✓$H{g^{ + + }}$
- B$KMn{O_4}$
- C$KCl{O_3}$
- D${K_2}C{r_2}{O_7}$
$C{H_3} - C{H_2} - C \equiv CH\mathop {\xrightarrow{{H{g^{ + + }}}}}\limits_{{H_2}O} \mathop {C{H_3} - C{H_2} - \mathop {\mathop C\limits^{||} }\limits^O - C{H_3}}\limits_{{\text{Butanone}}} $
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
| $[HI]$, $M$ | rate, $Ms^{-1}$ |
| $0.0500$ | $8.80 \times {10^{ - 10}}$ |
| $0.1000$ | $3.52 \times {10^{ - 9}}$ |
| $0.1500$ | $7.92 \times {10^{ - 9}}$ |

$\begin{array}{*{20}{c}}
{C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3} - CH - C{H_3}(excess) + B{r_2}\xrightarrow{{hv}}}
\end{array}$ $\mathop {\begin{array}{*{20}{c}}
{\,\,\,\,\,C{H_3}} \\
| \\
{C{H_3} - C - C{H_3}} \\
| \\
{\,\,Br}
\end{array}}\limits_{(A)} $ + $\mathop {\begin{array}{*{20}{c}}
{C{H_3}\,\,\,\,\,\,\,\,\,\,} \\
{\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3} - CH - C{H_2} - Br}
\end{array}}\limits_{(B)} $
the percentage yields of the products $(A)$ and $(B)$ are expected to be
$A \to B$ ${k_1} = {10^{15}}{e^{ - 25000/8.34\,T}}$
$C \to D$ ${k_2} = {10^{14}}{e^{ - 15000/8.34\,T}}$
Calculate the approximate temperature at which $k_1 = k_2$ ...... $K$