MCQ
$C{H_3} - C{H_2} - Cl $ $ \xrightarrow{alcKOH} $ $A$, the product is
- A$C{H_3}C{H_2}OK$
- B$C{H_3}CHO$
- C$C{H_3}C{H_2}OC{H_2}C{H_3}$
- ✓$C{H_2} = C{H_2}$
Haloalkanes in the presence of alcoholic $KOH$ undergoes elimination reaction or dehydrohalogenation reaction..
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$[HCl=36.5; {(N{H_4})_2}S{O_4}=132; N{H_3}=17]$
$[K_b\,(CH_3COO^-) =10^{-9},pK_a\,(HPh)=9.6,log\,2 =0.3]$