MCQ
$C{H_3} - CHO + HCN \to A$; Compound $A$ on hydrolysis gives
- A$C{H_3} - C{H_2} - COOH$
- B$C{H_3} - C{H_2} - C{H_2} - N{H_2}$
- C$C{H_3} - CO - COOH$
- ✓$C{H_3} - \mathop {\mathop {CH}\limits_{|\,\,\,\,\,\,} }\limits_{OH} - COOH$
✓
Answer
Correct option: D.
$C{H_3} - \mathop {\mathop {CH}\limits_{|\,\,\,\,\,\,} }\limits_{OH} - COOH$
d
$C{H_3}CHO + HCN \to $ $\mathop {\begin{array}{*{20}{c}}
{\,\,\,\,\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,OH\,\,} \\
\,\,\,|
\end{array}} \\
{C{H_3}C - C - CN} \\
{\,\,\,\,\,\,\,|} \\
{\,\,\,\,\,\,\,\,\,\,\,\,OH}
\end{array}}\limits_{{\kern 1pt} {\kern 1pt} {\kern 1pt} {\kern 1pt} {\kern 1pt} {\kern 1pt} {\kern 1pt} {\kern 1pt} {\text{(A)}}} \xrightarrow{{{H_3}{O^ + }}}$ $\begin{array}{*{20}{c}}
{\begin{array}{*{20}{c}}
{\,\,\,\,\,OH} \\
|
\end{array}\,\,\,\,\,\,\,} \\
{C{H_3} - C - COOH} \\
{|\,\,\,\,\,\,} \\
{H\,\,\,\,\,}
\end{array}$
$C{H_3}CHO + HCN \to $ $\mathop {\begin{array}{*{20}{c}}
{\,\,\,\,\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,OH\,\,} \\
\,\,\,|
\end{array}} \\
{C{H_3}C - C - CN} \\
{\,\,\,\,\,\,\,|} \\
{\,\,\,\,\,\,\,\,\,\,\,\,OH}
\end{array}}\limits_{{\kern 1pt} {\kern 1pt} {\kern 1pt} {\kern 1pt} {\kern 1pt} {\kern 1pt} {\kern 1pt} {\kern 1pt} {\text{(A)}}} \xrightarrow{{{H_3}{O^ + }}}$ $\begin{array}{*{20}{c}}
{\begin{array}{*{20}{c}}
{\,\,\,\,\,OH} \\
|
\end{array}\,\,\,\,\,\,\,} \\
{C{H_3} - C - COOH} \\
{|\,\,\,\,\,\,} \\
{H\,\,\,\,\,}
\end{array}$
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