MCQ
$CH_3-NH_2$ $\xrightarrow{{HN{O_2}}}$
- A$CH_3-OH$
- B$CH_3-N = N-OH$
- ✓$CH_3-O-CH_3$
- D$CH_3-N=O$
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$\left( A \right)\xrightarrow{{\operatorname{Re}duction}}\left( B \right)\xrightarrow{{HN{O_2}}}{C_2}{H_5}OH$