MCQ
$\mathrm{CH}_3-\mathrm{C} \equiv \mathrm{C} \ \text{MgBr}$ can be prepared by the reaction of $ ..........$
  • A
    $\mathrm{CH}_3-\mathrm{C} \equiv \mathrm{C}-\mathrm{Br}$ with $\mathrm{MgBr}_2$
  • B
    $\mathrm{CH}_3-\mathrm{C} \equiv \mathrm{CH}$ with $\mathrm{MgB}_2$
  • C
    $\mathrm{CH}_2-\mathrm{C} \equiv \mathrm{CH}$ with $\text{KBr}$ and $\text{Mg}$ metal
  • $\mathrm{CH}_3-\mathrm{C} \equiv \mathrm{CH}$ with $\mathrm{CH}_3 \mathrm{MgBr}$

Answer

Correct option: D.
$\mathrm{CH}_3-\mathrm{C} \equiv \mathrm{CH}$ with $\mathrm{CH}_3 \mathrm{MgBr}$
$\mathrm{CH}_3-\mathrm{C} \equiv \mathrm{C}-\mathrm{H}+\mathrm{CH}_3 \mathrm{MgBr} \rightarrow \mathrm{CH}_3-\mathrm{C} \equiv \mathrm{CMgBr}+\mathrm{CH}_4$.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free