MCQ
CH3​−C≡C MgBr can be prepared by the reaction of _________.
  • A
    CH3​−C≡C−Br with MgBr2
  • B
    CH3​−C≡CH with MgB2
  • C
    CH2​−C≡CH with KBr and Mg metal
  • D
    CH3​−C≡CH with CH3​MgBr

Answer

  1. CH3​−C≡CH with CH3​MgBr

Explanation:

CH3​−C≡C−H + CH3​MgBr → CH3​−C≡CMgBr + CH4​.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

The separation energy of the electron present in the shell $n = 3$ is $1.51\, eV.$ What is the energy in the first exicted state ? ............ $\mathrm{eV}$
Addition of water to this solution will not change [H3​O+].
The difference between electron gain enthalpies will be maximum between:
Heat of neutralisation of one equivalent of an acid by one equivalent of a base is  minimum when
Which of the following statement is/are wrong ?
A mixture of $1$ mole of $H _2 O$ and $1$ mole of $CO$ is taken in a $10$ litre container and heated to $725\,K$. At equilibrium $40 \%$ of water by mass reacts with carbon monoxide according to the equation :

$CO ( g )+ H _2 O ( g ) \rightleftharpoons CO _2( g )+ H _2( g )$ The equilibrium constant $K _{ C } \times 10^2$ for the reaction is $.......$ (Nearest integer)

The standard enthalpies of formation of CO2(g), H2O(l) and glucose(s) at 25°C are -400kJ/ mol, -300kJ/ mol and -1300kJ/ mol-1 respectively. The standard enthalpy of combustion per gram of glucose of 25°C is:
$STATEMENT$-$1$: In water, orthoboric acid behaves as a weak monobasic acid. because

$STATEMENT$-$2$: In water, orthoboric acid acts as a proton donor.

Consider the following four elements which are represented according to long form of periodic table- Here $W, Y$ and $Z$ are left, up and right elements with respect to the element $'X'\,'Y'$ belongs to $16^{th}$ group and $2^{nd}$ period. Then according to given information the incorrect statement regarding given element is
In which compound peroxide bond is present