MCQ
$C{H_3}CH = CHCHO$ is oxidized to $C{H_3}CH = CHCOOH$ using
- AAlkaline potassium permanganate
- ✓Acidified potassium permanganate
- CSelenium dioxide
- DOsmium tetroxide
✓
Answer
Correct option: B.
Acidified potassium permanganate
b
(b) $C{H_3} - CH = CH - CHO\mathop {}\limits_{} \xrightarrow[KMnO_4]{Acidic} C{H_3} - CH = CH - COOH$
(b) $C{H_3} - CH = CH - CHO\mathop {}\limits_{} \xrightarrow[KMnO_4]{Acidic} C{H_3} - CH = CH - COOH$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
The graph which represents the following reaction is :
→$\left( C _6 H _5\right)_3 C - Cl \frac{ OH ^{-}}{\text {Pyridine }}\left( C _6 H _5\right)_3 C - OH$
Which of the following will not give the iodoform test
Energy equivalent to one erg, one joule and one calorie is in the order
In which of the following reactions does the heat change represent the heat of formation of water
If moving proton, dutron and alpha particle have same De-Broglie wave length then which is correct order of their kinetic energy
Among $10^{-9} g$ (each) of the following elements, which one will have the highest number of atoms?
Element : Pb, Po, Pr and Pt
→Element : Pb, Po, Pr and Pt
Product of the above Friedel-Craft reaction is
$XeF_{2(g)} + H_{2(g)} \to 2HF_{(g)} + Xe_{(g)}\, \Delta H^o = -430\, kJ$
Bond energy $\to H-H = 435\, kJ/mol$
→Bond energy $\to H-H = 435\, kJ/mol$
$\to H-F = 565\, kJ/mol$
Calculate average bond energy of $Xe-F$ bond.....$ kJ/mol$
$I.U.P.A.C.$ name of above compound
→Which one has maximum electron affinity