MCQ
$CH_3CN$ $\xrightarrow{{Na + {C_2}{H_5}OH}}x$ The compound $x$ is
- A$CH_3CONH_2$
- ✓$CH_3CH_2NH_2$
- C$C_2H_6$
- D$CH_3NH-CH_3$
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$CH_3-CH=CH-CH_2-OH$ $\xrightarrow[{{S}_{{{N}^{1}}}}]{HBr}$ $[P]$
In the given reaction the product $[P]$ is :
$4NH_3 + 5O_2 \to 4NO + 6H_2O$