MCQ
$+\, CH_3SNa$ $\xrightarrow{{{C_2}{H_5}OH}}$ ?
The product formed is
- ✓$\begin{array}{*{20}{c}}
{C{H_3}SC{H_2} - CH - C{{(C{H_3})}_3}} \\
| \\
{OH}
\end{array}$ - B$\begin{array}{*{20}{c}}
{{{(C{H_3})}_3}C - CH - C{H_2}OH} \\
{|\,\,} \\
{\,\,\,\,\,\,\,SC{H_3}}
\end{array}$ - C$\begin{array}{*{20}{c}}
{C{H_3}SC{H_2} - CH - CH{{(C{H_3})}_2}} \\
| \\
{OH}
\end{array}$ - D$\begin{array}{*{20}{c}}
{{{(C{H_3})}_3}C - C{H_2}CH - SC{H_3}} \\
{\,\,\,\,\,\,\,\,\,\,\,\,|} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,OH}
\end{array}$
