- A$H_2O_{(g)} \longrightarrow H_2O_{(l)}$
- B$H_2O_{(l)} \longrightarrow H_2O_{(s)}$
- C${N_2} + 3{H_2} \longrightarrow 2N{H_3}$
- ✓$2O_{3(g)} \longrightarrow 3O _{2(g)}$
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$\begin{array}{*{20}{c}}
{C{H_3} - CH - CH = C{H_3}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}\xrightarrow{{HBr}}A$
$\begin{array}{*{20}{c}}
{C{H_3} - CH - CH = C{H_3}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}\xrightarrow{{HBr + ROOR}}B$
$\begin{array}{*{20}{c}}
{C{H_3} - CH - CH = C{H_3}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}\xrightarrow{{NBS}}C$
$Image$
$1.$ The structure of the product $\mathrm{I}$ is
A,B,C,D, $Image$
$2.$ The structures of compounds $J$ and $K$ respectively are
A,B,C,D, $Image$
$3.$ The structure of product $L$ is
A,B,C,D, $Image$
Give the answer question $1,2$ and $3.$