Question
Check the commutativity and associativity of the following binary operations:
'*' on N, defined by a * b = ab for all a, b ∈ N.

Answer

Commutativity: Let $\text{a, b}\in\text{N}.$ Then,

$\text{a}\ ^*\ \text{b}=\text{a}^{\text{b}}\neq\text{b}^{\text{a}}=\text{b}\ ^*\ \text{a}$

$\Rightarrow\ \text{a}\ ^*\ \text{b}\neq\text{b}\ ^*\ \text{a}$

⇒ '*' is not commutative on N.

Associativity: Let $\text{a, b, c}\in\text{N}.$ Then,

(a * b) * c = ab * c

= (ab)c = abc .....(i)

$\text{a}\ ^*\ (\text{b}\ ^*\ \text{c})=\text{a}\ ^*\ \text{b}^{\text{c}}=(\text{a})^{\text{b}^{\text{c}}}\ ....(\text{ii})$

From (i) and (ii)

$\text{a}^{\text{bc}}\neq(\text{a})^{\text{b}^{\text{c}}}$

$(\text{a}\ ^*\ \text{b})\ ^*\ \text{c}\neq\text{a}\ ^*\ (\text{b}\ ^*\ \text{c})$

⇒ '*' is not associative on N.

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