Question
Check the commutativity and associativity of the following binary operations:
'*' on Q defined by a * b = a + ab for all a, b ∈ Q.

Answer

Commutativity: Let $\text{a, b}\in\text{Q}.$ Then,

a * b = a + ab

b * a = b + ba

= b + ab

Therefore,

$\text{a}\ ^*\ \text{b}\neq\text{b}\ ^*\ \text{a}$

Thus, * is not commutative on Q.

Associativity: Let $\text{a, b, c}\in\text{Q}.$ Then,

a * (b * c) = a * (b + bc)

= a + a(b + bc)

= a + ab + abc

(a * b) * c = (a + ab) * c

= (a + ab) + (a + ab)c

= a + ab + ac + abc

Therefore,

$\text{a}\ ^*\ (\text{b}\ ^*\ \text{c})\neq(\text{a}\ ^*\ \text{b})\ ^*\ \text{c}$

Thus, * is not associative on Q.

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