MCQ
Chlorine cannot be used
  • A
    As bleaching agent
  • B
    In sterilisation
  • C
    In preparation of antiseptic
  • For extraction of silver and copper

Answer

Correct option: D.
For extraction of silver and copper
d
Chlorine can be used as bleaching agent. It can be used in sterilization and preparation of antiseptic. But is not used for extraction of Silver and Copper.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Which of the following has zero valency
The cyanide ion, $C{N^ - }$ and ${N_2}$ are isoelectronic. But in contrast to $C{N^ - },$ ${N_2}$ is chemically inert because of
Zeise's salt is
Mark the correct statement:
In a complexometric tritration of metal ion with ligand $M$ (Metalion) $+L$ (Ligand) $\to $ $C$ (Complex) end point is estimated spectrophotometrically (through light absorption) If $'M'$  and $'C'$  do not absorb light and only $'L'$  absorbs, then the titration plot between absorbed light $(A)$  versus volume of ligand $'L'$  $(V)$  would look like
There is no $S-S$ linkage is
If $1\,M$ and $2.5\,litre$  $NaOH$ solution is mixed with another $ 0.5\,M$ and $3\,litre$ $ NaOH$  solution, then molarity of the resultant solution will be ........ $M$.
Given below are the half-cell reactions :

$Mn^{2+} +2e- \rightarrow Mn;\, E^o = -1.18\,V$

$2(Mn^{3+} +e^- \rightarrow Mn^{2+} )\,;\,E^o=+1.51\,V$

The $E^o$ for $3Mn^{2+} \rightarrow Mn+ 2Mn^{3+}$ will be :

From the following ${E^o}$ values of half cells, what combination of two half cells would result in a cell with the largest potential ?

$\left( I \right)A + {e^ - } \to {A^\circleddash  }\,\,\,\,\,\,{E^o} =  + 0.24\,V$

$\left( {II} \right){B^ - } + {e^ - } \to {B^{ - 2}}\,\,\,\,\,\,{E^o} =  + 1.25\,V$

$\left( {III} \right){C^ - } + 2{e^ - } \to {C^{ - 3}}\,\,\,\,\,\,{E^o} =  + 0.15\,V$

$\left( {IV} \right)D + 2{e^ - } \to {D^{ - 2}}\,\,\,\,\,\,{E^o} =  + 0.68\,V$

At $298\, K$ the $emf$ of cell is ............ $\mathrm{V}$

$\operatorname{P}t|{{H}_{{{2}_{\left( 2\,atm \right)}}}}|H_{\left( 0.02\,M \right)}^{\oplus }||H_{\left( 0.1\,M \right)}^{\oplus }|{{H}_{{{2}_{\left( 1\,atm \right)}}}}|Pt$