MCQ
Chlorine is in $+1$ oxidation state in
- A$HCl$
- B$HCl{O_4}$
- C$ICl$
- ✓$C{l_2}O$
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Choose the correct answer from the options given below:
$(1)$ $PtCl_4·5NH_3$ $(2)$ $PtCl_4·4NH_3$
$(3)$ $PtCl4·3NH_3$ $(4)$ $PtCl4·2NH_3$
image$\mathop {\xrightarrow{{NaN{O_2}}}}\limits_{HCl} A\,\,\xrightarrow{{CuCN}}B\,\,\mathop {\xrightarrow{{{H_2}}}}\limits_{Ni} C\,\,\xrightarrow{{HN{O_2}}}D$
$C{H_3}C{H_2}COOH\xrightarrow{{SOC{l_2}}}\,B\,$$ \xrightarrow{{N{H_3}}}\,C\,\xrightarrow[{B{r_2}}]{{KOH}}\,D$
The structure of $D$ would be