MCQ
Chloropicrin is obtained by the reaction of
- AChlorine on picric acid
- ✓Nitric acid on chloroform
- CSteam on carbon tetrachloride
- DNitric acid on chlorobenzene
$CHC{{l}_{3}}+HON{{O}_{2}}\to \underset{\text{chloropicrin}}{\mathop{CN{{O}_{2}}C{{l}_{3}}}}\,+{{H}_{2}}O$
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$(A)\,{{C}_{8}}{{H}_{10}}\xrightarrow{KMn{{O}_{4}}}(B){{C}_{8}}{{H}_{6}}{{O}_{4}}\xrightarrow[Fe]{B{{r}_{2}}}{{C}_{8}}{{H}_{5}}Br{{O}_{4}}(C)$ (one-product only)
(Given atomic number $\mathrm{Sc}: 21, \mathrm{Ti}: 22, \mathrm{~V}: 23, \mathrm{Cr}$ : $24, \mathrm{Mn}: 25, \mathrm{Fe}: 26)$
$(A)$ $E_a = 0$
$(B)$ $T$ $=$ $\infty $
$(C)$ $T = 0$
$(D)$ $E_a$ $=$ $\infty $