MCQ
Choose the correct answer from the given four option.The differential equation $\text{y}\frac{\text{d}\text{y}}{\text{d}\text{x}}+\text{x}=\text{C}$ represents:
  • A
    Family of hype.
  • B
    Family of parabolas.
  • C
    Family of ellipses.
  • Family of circles.

Answer

Correct option: D.
Family of circles.
Given that, $\text{y}\frac{\text{d}\text{y}}{\text{d}\text{x}}+\text{x}=\text{C}$
$\Rightarrow\text{y}\frac{\text{d}\text{y}}{\text{d}\text{x}}=\text{C}-\text{x}$
$\Rightarrow\text{ydy}=(\text{C}-\text{x})\text{dx}$
On integrating both sides, we get
$\int\text{ydy}=\int(\text{C}-\text{x})\text{dx}$
$\Rightarrow\frac{\text{y}^2}{2}=\text{Cx}-\frac{\text{x}^2}{2}+\text{k}$
$\Rightarrow\frac{\text{x}^2}{2}+\frac{\text{y}^2}{2}=\text{Cx}+\text{k}$
$\Rightarrow\frac{\text{x}^2}{2}+\frac{\text{y}^2}{2}-\text{Cx}=\text{k}$
which represent family of circles.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

$\int {\frac{{\sin \,\frac{{5x}}{2}}}{{\sin \,\frac{x}{2}}}} dx$ is equal to (where $c$ is a constant of integration).
Let $a,b \in R,\left( {a \ne 0} \right)$. if the function $f$ defined as

$f\left( x \right)\left\{ \begin{array}{l}
\frac{{2{x^2}}}{a}\,\,\,\,\,\,\,\,\,\,\,\,,\,\,\,\,\,0 \le x < 1\,\,\,\\
a\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,,\,\,\,\,\,1 \le x < \sqrt 2 \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\\
\frac{{2{b^2} - 4b}}{{{x^3}}}\,\,\,,\,\,\,\,\,\sqrt 2  \le x < \infty 
\end{array} \right.\,\,\,\,$ 

is continuous in the interval $\left[ {0,\infty } \right)$ , then an ordered pair $(a, b)$ is

The order of the differential equation $\Bigg[1+\Big(\frac{\text{dy}}{\text{dx}}\Big)^5\Bigg]^\frac{2}{3}=\frac{\text{d}^3\text{y}}{\text{dx}}$ is:
Let $f(x) = \left\{ {\begin{array}{*{20}{c}}{|x|,\,0 < \,|x|\, \le 2}\\{\,\,1\,\,\,,\,\,x = 0\,\,\,\,\,\,\,\,\,}\end{array}} \right.$, then at $x = 0$ $f$ has
Find the determinant of the matrix $\text{A}=\begin{bmatrix}-\cos\theta&-tan\theta\\\cot\theta&\cos\theta\end{bmatrix}$ is:
For the system of linear equations :

$x-2 y=1, x-y+k z=-2, k y+4 z=6, k \in R$

consider the following statements :

$(A)$ The system has unique solution if $k \neq 2$, $k \neq-2$

$(B)$ The system has unique solution if $k =-2$.

$(C)$ The system has unique solution if $k =2$.

$(D)$ The system has no-solution if $k =2$.

$(E)$ The system has infinite number of solutions if $k \neq-2$

Which of the following statements are correct?

Let $A =\{1,2,3,4, \ldots .10\}$ and $B =\{0,1,2,3,4\}$ The number of elements in the relation $R =\{( a , b )$ $\left.\in A \times A : 2( a - b )^2+3( a - b ) \in B \right\}$ is $.........$.
The sum of infinite series ${\tan ^{ - 1}}\left( {\frac{2}{{1 - {1^2} + {1^4}}}} \right) + {\tan ^{ - 1}}\left( {\frac{4}{{1 - {2^2} + {2^4}}}} \right) + {\tan ^{ - 1}}\left( {\frac{6}{{1 - {3^2} + {3^4}}}} \right) + .....$ is
If $\vec{\text{a}},\vec{\text{b}},\vec{\text{c}}$ are three non-coplanar vectors, then $\big(\vec{\text{a}}+\vec{\text{b}}+\vec{\text{c}}\big).\big[\big(\vec{\text{a}}+\vec{\text{b}}\big)\times\big(\vec{\text{a}}+\vec{\text{c}}\big)\big]$ equals:
If $a,b$ and $c$ are perpendicular to $b + c,c + a$and $a + b$ respectively and if $|a + b| = 6,|b + c| = 8$ and $|c + a| = 10$ then $|a + b + c| = $