MCQ
Choose the correct answer from the given four options.If $\text{P}(\text{A})=0.4,\text{P}(\text{B})=0.8$ and $\text{P}\Big(\frac{\text{B}}{\text{A}}\Big)=0.6,$ then $\text{P}(\text{A}\cup\text{B})$ is equal to:
  • A
    $0.24$
  • B
    $0.3$
  • C
    $0.48$
  • $0.96$

Answer

Correct option: D.
$0.96$
Here$, P(A) = 0.4, P(B) = 0.8$
and $\text{P}\Big(\frac{\text{B}}{\text{A}}\Big)=0.6,$
$\because\text{P}\Big(\frac{\text{B}}{\text{A}}\Big)=\frac{\text{P}(\text{B}\cap\text{A})}{\text{P}(\text{A})}$
$\Rightarrow\text{P}(\text{B}\cap\text{A})=\text{P}\Big(\frac{\text{B}}{\text{A}}\Big)\cdot\text{P}(\text{A})$
$=0.6\times0.4=0.24$
$=1.2-0.24=0.96$

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