MCQ
Choose the correct answer.
If – 3x + 17 < – 13, then:
If – 3x + 17 < – 13, then:
- A$\text{x}\in(10, \infty)$
- B$\text{x}\in[10, \infty)$
- C$\text{x}\in(-\infty\text{j},10]$
- D$\text{x}\in[-10, 10)$
Solution:
Given that - 3x + 17 < - 13
⇒ - 3x < - 17 - 13
⇒ -3x < - 30
⇒ 3x > 30
⇒ x > 10
$\Rightarrow\text{x}\in(10, \infty)$
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