MCQ
Choose the correct answer.
If z is a complex number, then:
  • A
    $|\text{z}^2|>|\text{z}|^2$
  • B
    $|\text{z}^2|=|\text{z}|^2$
  • C
    $|\text{z}^2|<|\text{z}|^2$
  • D
    $|\text{z}^2|\geq|\text{z}|^2$

Answer

  1. |z|2 = |z2|

Solution:

Let z = x + yi

|z| = |x + yi| and |z|2 = |x + yi|2

⇒ |z|2 = x2 + y2 .....(i)

Now, z2 = x2 + y2i2 + 2xyi

z2 = x2 - y2 + 2xyi

$|\text{z}^2|=\sqrt{(\text{x}^2-\text{y}^2)^2+(2\text{xy})^2}$

$=\sqrt{\text{x}^4+\text{y}^4-2\text{x}^2\text{y}^2+4\text{x}^2\text{y}^2}$

$=\sqrt{\text{x}^4+\text{y}^4+2\text{x}^2\text{y}^2}$

$=\sqrt{(\text{x}^2+\text{y}^2)^2}$

So, $|\text{z}|^2=\text{x}^2+\text{y}^2=|\text{z}|^2$

So, $|\text{z}|^2=|\text{z}^2|$

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