MCQ
Choose the correct answer.
$\lim\limits_{\text{x} \rightarrow \pi}\frac{\sin\text{x}}{\text{x}-\pi}$ is:
$\lim\limits_{\text{x} \rightarrow \pi}\frac{\sin\text{x}}{\text{x}-\pi}$ is:
- A1
- B2
- C-1
- D-2
Solution:
Given, $\lim\limits_{\text{x} \rightarrow \pi}\frac{\sin\text{x}}{\text{x}-\pi}=\lim\limits_{\text{x} \rightarrow\pi}\frac{\sin(\pi)-\text{x}}{-(\pi-\text{x})}$
$=-1$
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The value of $\sin\frac{\pi}{18}+\sin\frac{\pi}{9}+\sin\frac{2\pi}{9}+\sin\frac{5\pi}{18}$ is given by:
$\sin\frac{7\pi}{18}+\sin\frac{4\pi}{9}$
$1$
$\cos\frac{\pi}{6}+\cos\frac{3\pi}{7}$
$\cos\frac{\pi}{9}+\sin\frac{\pi}{9}$
Angle made by line with measured anticlockwise is called inclination of the line: