MCQ
Choose the correct answer.
The value of $\tan75^\circ-\cot75^\circ$ is equal to:
The value of $\tan75^\circ-\cot75^\circ$ is equal to:
- A$2\sqrt{3}$
- B$2+\sqrt{3}$
- C$2-\sqrt{3}$
- D$1$
Solution:
$\tan75^\circ-\cot75^\circ=\frac{\sin75^\circ}{\cos75^\circ}-\frac{\cos75^\circ}{\sin75^\circ}\\=\frac{2(\sin^275^\circ-\cos^275^\circ)}{2\sin75^\circ\cos75^\circ}=\frac{-2\cos150^\circ}{\sin150^\circ}$
$=-2\cot150^\circ=-2\cot(180^\circ-30^\circ)=2\cot30^\circ=2\sqrt3$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$\frac{\pi}{6}$
$\frac\pi3$
$\frac\pi4$
$\frac{5\pi}{12}$
If (a, b) lies on circle with centre as origin, then its radius will be: