
- A'$A$' and '$B$' are both Markovnikov addition products.
- ✓'$A$' is Markovnikov product and '$B$'is anti-Markovnikov product.
- C'$A$' and '$B$' are both anti-Markovnikov products.
- D'$B$' is Markovnikov and '$A$' is anti-Markovnikov product.


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Reason $(R)$ : Oxygen forms $\mathrm{p} \pi-\mathrm{p} \pi$ multiple bonds with itself and other elements having small size and high electronegativity like $\mathrm{C}, \mathrm{N}$, which is not possible for sulphur.
In the light of the above statements, choose the most appropriate answer from the options given below :

$\left[\mathrm{CoCl}\left(\mathrm{NH}_3\right)_5\right]^{2+}, \quad\left[\mathrm{Co}(\mathrm{CN})_6\right]^{3-} \text {, }$
$(A)$ $(B)$
$\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5\left(\mathrm{H}_2 \mathrm{O}\right)\right]^{3+}, \quad\left[\mathrm{Cu}\left(\mathrm{H}_2 \mathrm{O}\right)_4\right]^{2+}$
$(C)$ $(D)$
The correct order of $A$, $B$, $C$ and $D$ in terms of wavenumber of light absorbed is :