Thus is does have plane of symmetry.
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$A.$ The electron gain enthalpy of $F$ is more negative than that of $Cl$
$B.$ Ionization enthalpy decreases in a group of periodic table
$C.$ The electronegativity of an atom depends upon the atoms bonded to it.
$D.$ $Al _2 O _3$ and $NO$ are examples of amphoteric oxides.
Choose the most appropriate answer from the options given below:
$Cr_2O_7^{2-}$ ( $aq$ $1\,M$ ) $+ 14H^+(aq) + 6e^-$ $\rightarrow 2Cr^{+3} (aq,\,1\,M) + 7H_2O (l)$
$\mathop {C{H_3} - \mathop C\limits^ \oplus H - C{H_3}}\limits_I $
$\mathop {C{H_3} - \mathop C\limits^ \oplus H - OC{H_3}}\limits_{II} $
$\mathop {C{H_3} - \mathop C\limits^ \oplus H - C{H_2} - OC{H_3}}\limits_{III} $
$(A)$Covalent radius decreases down the group from $\mathrm{C}$ to $\mathrm{Pb}$ in a regular manner.
$(B)$ Electronegativity decreases from $\mathrm{C}$ to $\mathrm{Pb}$ down the group gradually.
$(C)$ Maximum covalence of $\mathrm{C}$ is $4$ whereas other elements can expand their covalence due to presence of $d$ orbitals.
$(D)$ Heavier elements do not form $\mathrm{p} \pi-p \pi$ bonds.
$(E)$ Carbon can exhibit negative oxidation states.
Choose the correct answer from the options given below: