MCQ
Coloration of $B{r_2}/CC{l_4}$ will be discharged by
- ✓Cinnamic acid
- BBenzoic acid
- C$o-$ phthalic acid
- DAcetophenone
✓
Answer
Correct option: A.
Cinnamic acid
a
Cinnamic acid reacts with bromine in carbon tetrachloride to give dibromocinnamic acid.
Cinnamic acid reacts with bromine in carbon tetrachloride to give dibromocinnamic acid.
${{C}_{6}}{{H}_{5}}CH=CHCOOH+B{{r}_{2}}$ $\xrightarrow{CC{{l}_{4}}}$ $\underset{\text{dibromo}\,\,\,\text{cinnamic acid}}{\mathop{\begin{matrix}
\,\,\,\,Br\,\,\,\,\,\,\,\,\,\,\,\,Br\,\,\,\,\,\,\,\, \\
|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\, \\
{{C}_{6}}{{H}_{5}}CH-CHCOOH \\
\end{matrix}}}\,$
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