MCQ
Common alum is
- ✓${K_2}S{O_4}.A{l_2}{(S{O_4})_3}.24{H_2}O$
- B${K_2}S{O_4}.C{r_2}{(S{O_4})_3}.24{H_2}O$
- C${K_2}S{O_4}.F{e_2}{(S{O_4})_3}.24{H_2}O$
- D${(N{H_4})_2}S{O_4}.FeS{O_4}.6{H_2}O$
$K _2 SO _4 \cdot Al _2\left( SO _4\right)_3 \cdot 24 H _2 O$
Ammonium alum is $\left( NH _4\right) SO _4 \cdot Al _2\left( SO _4\right)_3 \cdot 24 H _2 O$.
Chrome alum is $K _2 SO _4 \cdot Cr _2\left( SO _4\right)_3 \cdot 24 H _2 O$
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$(I)\,[Cr(NO_3)_3(NH_3)_3]$ $(II)\, K_3[Fe(C_2O_4)_3]$ $(III)\,[CoCl_2(en)_2]^+$ $(IV)\, [CoBrCl(ox)_2]^{3-}$
${N_2}(g)\, + 3{H_2}(g)\, \rightleftharpoons \,2N{H_3}(g)$
The equilibrium constant of the above reaction is $K_3$. If pure ammonia is left to dissociate, the partial pressure of ammonia at equilibrium is given by (Assume that $P_{NH_3}<\,< P_{total}$ at equilibrium)