
- ✓$(i) > (ii) > (iii)$
- B$(ii) > (i) > (iii)$
- C$(i) > (iii) > (ii)$
- D$(ii) > (iii) > (i)$

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$\begin{array} {|l|p{0.6\linewidth}|} \hline List\,\,I\,\,Equations & List\,\,II\,\,Type\,\,of\,\,processes \\ \hline A. K_p > Q & (i)\,\,Non-\,\,spontaneous \\ \hline B.\, \Delta G^o < RT ln Q & (ii)\,\,Equilibrium \\ \hline C. K_p=Q & (iii)\,\,Spontaneous\,\,and\,\,endothermic \\ \hline D. T > \frac{\Delta H}{\Delta S} & (iv)\,\,Spontaneous \\ \hline \end{array}$
$\frac{1}{2}C{l_2}(g)\xrightarrow{{\frac{1}{2}{\Delta _{diss}}{H^\Theta }}}Cl(g)\xrightarrow{{{\Delta _{eg}}{H^\Theta }}}$ $C{l^ - }(g)\xrightarrow{{{\Delta _{Hyd}}{H^\Theta }}}C{l^ - }(aq)$
(using the data,
${{\Delta _{diss}}H_{C{l_2}}^\Theta } = 240\,kJ\,mol^{-1}, {{\Delta _{eg}}H_{C{l}}^\Theta }= -349 \,kJ\,mol^{-1},$${{\Delta _{Hyd}}H_{C{l}}^\Theta }= -381 \,kJ\,mol^{-1}$ ) will be ............. $\mathrm{kJ\,mol}^{-1}$