Question
Complete the following conversion.
$CH _3- CH = CH _2+\underset{\text { (Cold conc.) }}{ H _2 SO _4} \longrightarrow \underset{\Delta}{\text { H-OH }}$
$CH _3- CH = CH _2+\underset{\text { (Cold conc.) }}{ H _2 SO _4} \longrightarrow \underset{\Delta}{\text { H-OH }}$