Question
Complete the following reaction, $\text{CH}_2=\text{CH}_2+\text{Cl}_2\rightarrow$
$\text{CH}_2=\text{CH}_2+\text{Cl}_2\rightarrow\text{CH}_2-\text{CH}_2 \\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ | \ \ \ \ \ \ \ \ \ \ \ |\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{Cl} \ \ \ \ \ \ \ \ \text{Cl}$
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$\text{CH}_3\text{COOH}+\text{CH}_3\text{CH}_2\text{OH}\xrightarrow{\ \ \text{Conc. H}_2\text{SO}_4\ \ \ }\text{CH}_3\text{COOC}_2\text{H}_5+\text{H}_2\text{O}$
$\text{Al(OH)}_3\xrightarrow{\ \ \ \ \ \ \ \ \ \ \ }\text{Al}_2\text{O}_3\ +\ \text{H}_2\text{O}$