86Rn220→84Po216+ __________:
- A$\beta$
- B$\gamma$
- C$\alpha$
- D$\text{H}^1_1$
Explanation:
86Rn220 → 84Po216 + ZXA
Z + 84 = 86 and 220 = 216 + A
So, Z = 2 and A = 4
$2\alpha^4$
So, it is $\alpha$ particle.
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