MCQ
Complex $[Co(NH_3)5Br]SO_4$ and $[Co(NH_3)_5SO_4]Br$ can be identified by
- A$BaCl_2$
- B$AgNO_3$
- C$PbCl_2$
- ✓All of these
✓
Answer
Correct option: D.
All of these
d
Counter ions $So_4^{-2}$ and $Br^-$ can be detected by all due to formation of $BaSO_4, AgBr, PbSO_4$
Counter ions $So_4^{-2}$ and $Br^-$ can be detected by all due to formation of $BaSO_4, AgBr, PbSO_4$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
What happens when $2-$ hydroxy benzoic acid is distilled with zinc dust, it gives
→Which of the following compound is the strongest base
The final product $[D]$ of the reaction is
→$CHCl_3\xrightarrow[hv]{O_2}[A]\xrightarrow{EtOH}[B]\xrightarrow{2\ mole\ MeMgBr}$
$[C]\xrightarrow{CaOCl_2}[D]\xrightarrow{\Delta}CH_3-\underset{\underset{O}{||}}{C}-CH_3$
Assertion : Cyanide $(CN^-)$ is a strong nucleophile.
Reason : Benzonitrile is prepared by the reaction of chlorobenzene with potassium cyanide.
→Reason : Benzonitrile is prepared by the reaction of chlorobenzene with potassium cyanide.
Chromatographic technique/s based on the principle of differential adsorption is/are
→$A$. Column chromatography
$B$. Thin layer chromatography
$C$. Paper chromatography
Choose the most appropriate answer from the options given below:
Major product for the above reaction is :
For a reaction $A \xrightarrow{ K _1} B \xrightarrow{ K _2} C$ If the rate of formation of $B$ is set to be zero then the concentration of $B$ is given by :
→$9.3 \mathrm{~g}$ of pure aniline upon diazotisation followed by coupling with phenol gives an orange dye. The mass of orange dye produced (assume $100$% yield/ conversion) is . . . . . $g$. (nearest integer)
→Point out the wrong statement :For a first order reaction
When electricity is passed through the solution of $AlC{l_3},\,\,13.5\,\,gm$ of $Al$ are deposited. The number of Faraday must be
→