Compound PdCl_4.6H_2O is a hydrated complex; 1 molal aqueous solu… - Vidyadip

MCQ

Compound $PdCl_4.6H_2O$ is a hydrated complex; $1$ molal aqueous solution of it has freezing point $269.28\ K$ . Assuming $100\%$ ionization of complex, calculate the molecular formula of the complex ($K_f$ for water $ = 1.86\ K\ kg\,mol^{-1}$)

A
$\left[ {Pd{{\left( {{H_2}O} \right)}_6}} \right]C{l_4}$
✓
$\left[ {Pd{{\left( {{H_2}O} \right)}_4}C{l_2}} \right]C{l_2}.2{H_2}O$
C
$\left[ {Pd{{\left( {{H_2}O} \right)}_3}C{l_3}} \right]Cl.3{H_2}O$
D
$\left[ {Pd{{\left( {{H_2}O} \right)}_2}C{l_4}} \right]4{H_2}O$

✓

Answer

Correct option: B.

$\left[ {Pd{{\left( {{H_2}O} \right)}_4}C{l_2}} \right]C{l_2}.2{H_2}O$

b
$P_{0}=76$

$P_{s}=38$

$\frac{P_{0}-P_{s}}{P_{s}}=1=\frac{i(1)}{(2)}$

$\mathrm{i}=2=1+(2) \propto$

$2 \propto=1$

$\alpha=\frac{1}{2}$

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