MCQ
Comproportionation occurs between
- A$C{l^ - }(aq.) + Cl{O^ - }(aq.) + O{H^ - }(aq.)$
- B$P{H_3}(g) + {H_3}P{O_4}$ acid
- C$N{a_2}S(aq.) + N{a_2}S{O_3}(aq.)$
- ✓$MnO_4^ - (aq.) + M{n^{2 + }}(aq.) + ZnS{O_4}(aq.)$
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${H_2}O\left( g \right) + C\left( s \right) \to CO\left( g \right) + {H_2}\left( g \right);\Delta H = 131\,kJ$
$CO\left( g \right) + \frac{1}{2}{O_2}\left( s \right) \to C{O_2}\left( g \right);\Delta H = - 282\,kJ$
${H_2}\left( g \right) + \frac{1}{2}{O_2}\left( s \right) \to {H_2}O\left( g \right);\Delta H = - 242\,kJ$
$C(s) + O_2(g) \to CO_2(g); \Delta H = X\,kJ$
The value of $X$ will be......$kJ$
$CH \equiv CH\xrightarrow[{(excess)}]{{NaN{H_2}/liq.N{H_3}}}A\xrightarrow{{2C{H_3} - I}}B\xrightarrow[{quinolene}]{{{H_2}/Pd - BaS{O_4}}}C$
$C\xrightarrow[{quinolene}]{{{H_2}/Pd - BaS{O_4}}}\xrightarrow[{liq.\,N{H_3}}]{{NaN{H_2}}}D$