Question
Compute: $\left(\frac{56}{28}\right)^0 \div\left(\frac{2}{5}\right)^3 \times \frac{16}{25}$

Answer

$ \left(\frac{56}{28}\right)^0 \div\left(\frac{2}{5}\right)^3 \times \frac{16}{25}$
$ =1 \div \frac{2^3}{5^3} \times \frac{2 \times 2 \times 2 \times 2}{5 \times 5}$
$ {\left[\because\left(\frac{56}{28}\right)^0=1\right]}$
$ =1 \times \frac{5^3}{2^3} \times \frac{2^4}{5^2}=5^{3-2} \times 2^{4-3}$
$ =5^1 \times 2^1=10$

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