MCQ
Conc. $H_2SO_4$ cannot be used to prepare $HBr$ from $NaBr$ because it :
- ✓reacts slowly with $NaBr$
- Boxidises $HBr$ into $Br_2$
- Creduces $HBr$
- Ddisproportionates $HBr$
✓
Answer
Correct option: A.
reacts slowly with $NaBr$
a
$\mathop {HOCl}\limits_{( + 1)} < \mathop {HCl{O_2}}\limits_{( + 3)} < \mathop {HCl{O_3}}\limits_{( + 5)} < \mathop {HCl{O_4}}\limits_{( + 7)} $
$\mathop {HOCl}\limits_{( + 1)} < \mathop {HCl{O_2}}\limits_{( + 3)} < \mathop {HCl{O_3}}\limits_{( + 5)} < \mathop {HCl{O_4}}\limits_{( + 7)} $
Acidic nature $ \propto EN \propto + O.S.$
For compounds of an element
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