Conc. H_2 S O_4 reacts with C_2 H_5 OH at 170 ,^o C to form

MCQ

Conc. ${H_2}S{O_4}$ reacts with ${C_2}{H_5}OH$ at ${170\,^o}C$ to form

A
$C{H_3}COC{H_3}$
B
$C{H_3}COOH$
C
$C{H_3}CHO$
✓
${C_2}{H_4}$

✓

Answer

Correct option: D.

${C_2}{H_4}$

d
(d)$\underset{\text{Ethanol}}{\mathop{{{C}_{2}}{{H}_{5}}OH}}\,\underset{{{170}\,^{o}}C}{\mathop{\xrightarrow{Conc.\,{{H}_{2}}S{{O}_{4}}}}}\,\underset{\text{Ethane}}{\mathop{{{C}_{2}}{{H}_{4}}}}\,+{{H}_{2}}O$

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Match List $I$ with List $II$

List $I$ Oxide	List $II$ Type of Bond
$A$ $N _2 O _4$	$I$. $1 N = O$ bond
$B$ $NO _2$	$II$. $1 N - O - N$ bond
$C$ $N _2 O _5$	$III$. $1 N - N$ bond
$D$ $N _2 O$	$IV$. $1 N = N / N \equiv N$ bond