MCQ
Concentrated ${H_2}S{O_4}$ cannot be used to prepare $HBr$ from $NaBr$, because it
- AReduces $HBr$
- ✓Oxidises $HBr$
- CDisproportionates $HBr$
- DReacts slowly with $NaBr$
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$2 \mathrm{H}_{2} \mathrm{O} \rightarrow \mathrm{O}_{2}+4 \mathrm{H}^{\oplus}+4 \mathrm{e}^{-} ; \mathrm{E}_{\mathrm{red}}^{0}=1.23 \mathrm{V}$
$(\mathrm{R}=8.314 \;\mathrm{J} \mathrm{mol}^{-1} \mathrm{K}^{-1} ; \text { Temperature }=298 \;\mathrm{K} ;$ oxygen under std. atm. pressure of $1 \;bar$)
true about this mechanism
