MCQ
Configuration of $Yb^{+2}$ is
- A$[Xe]\,4f^{14}\, 5d^1$
- ✓$[Xe]\,4f^{14}$
- C$[Xe]\,4f^{14}\, 6s^2$
- D$[Xe]\,4f^{14}\,5d^1\,6s^2$
hence $Yb^{+2}$ is $[Xe]\,4f^{14}$
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|
List$-I$ (Chemical Reaction) |
List$-II$ (Reagent used) |
| $(a)$ $\mathrm{CH}_{3} \mathrm{COOCH}_{2} \mathrm{CH}_{3} \rightarrow \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}$ |
$(i)$ $\mathrm{CH}_{3} \mathrm{MgBr} / \mathrm{H}_{3} \mathrm{O}^{+}$ $(1 .$ equivalent $)$ |
| $(b)$ $\mathrm{CH}_{3} \mathrm{COOCH}_{3} \rightarrow \mathrm{CH}_{3} \mathrm{CHO}$ | $(ii)$ $\mathrm{H}_{2} \mathrm{SO}_{4} / \mathrm{H}_{2} \mathrm{O}$ |
| $(c)$ $\mathrm{CH}_{3} \mathrm{C} \equiv \mathrm{N} \rightarrow \mathrm{CH}_{3} \mathrm{CHO}$ | $(iii)$ $\mathrm{DIBAL}-\mathrm{H} / \mathrm{H}_{2} \mathrm{O}$ |
| $(d)$ $\mathrm{CH}_{3} \mathrm{C} \equiv \mathrm{N} \rightarrow \mathrm{CH}_{3}CO\mathrm{CH}_{3}$ | $(iv)$ $\mathrm{SnCl}_{2}, \mathrm{HCl} / \mathrm{H}_{2} \mathrm{O}$ |
Choose the most appropriate match :