MCQ
Conjugate acid of $HPO_4^{-2}$ is
- A$H_3PO_4$
- ✓${H_2}PO_4^\Theta $
- C$PO_4^{ - 3}$
- D${H_2}PO_3^\Theta $
$H _2 PO _4^{-} \rightarrow H ^{+}+ HPO _4^{2-}$
The base and its conjugate acid differ by one proton only.
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$A.$ For 1 s orbital, the probability density is maximum at the nucleus.
$B.$ For $2 s$ orbital, the probability density first increases to maximum and then decreases sharply to zero.
$C.$ Boundary surface diagrams of the orbitals encloses a region of $100 \%$ probability of finding the electron.
$D.$ $p$ and d-orbitals have $1$ and $2$ angular nodes respectively.
$E.$ Probability density of p-orbital is zero at the nucleus.