MCQ
Conjugate base of $HSO_4^ - $ is
- ✓$SO_4^{2 - }$
- B${H_2}S{O_4}$
- C${H_3}SO_4^ + $
- DNone of these
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$C{H_3}C{H_2}CH = CHC{H_3}$ $\xrightarrow{X}C{H_3}C{H_2}COOH\, + \,C{H_3}COOH$
The $X$ is

| Column $-I$ | Column $-II$ |
| $(A)$ Ionisation potential | $(P)$ $O < F < N$ |
| $(B)$ Electronegativity | $(Q)$ $N < O < F$ |
| $(C)$ $Z_{eff}$ | $(R)$ $O < N < F$ |
| $(D)$ Electron affinity | $(S)$ $N < C< O$ |

Given: $\Delta H ^0=-54.07\,kJ\,mol ^{-1}$
$\Delta S ^{\circ}=10\,JK ^{-1}\,mol ^{-1}$
(Take $2.303 \times 8.314 \times 298=5705$ )