MCQ
Consider the given standard electrode potentials :
$\ce{i}.\frac{\text{K}^+}{\text{K}}=-3.02\text{V}$
$\ce{ii}.\frac{\text{Cu}^{2+}}{\text{Cu}}=+0.34\text{V}$
$\ce{iii}.\frac{\text{Hg}^{2+}}{\text{Hg}}=0.92\text{V}$
$\ce{iv}.\frac{\text{Cr}^{3+}}{\text{Cr}}=-0.74\text{V}$
Decreasing order of reducing power of these elements is :
$\ce{i}.\frac{\text{K}^+}{\text{K}}=-3.02\text{V}$
$\ce{ii}.\frac{\text{Cu}^{2+}}{\text{Cu}}=+0.34\text{V}$
$\ce{iii}.\frac{\text{Hg}^{2+}}{\text{Hg}}=0.92\text{V}$
$\ce{iv}.\frac{\text{Cr}^{3+}}{\text{Cr}}=-0.74\text{V}$
Decreasing order of reducing power of these elements is :
- A$\text{I > II > III > IV}$
- B$\text{I > IV > III > II}$
- ✓$\text{I > IV > II > III}$
- D$\text{III > II > IV > I}$