- AThe hybridisation state of $N$ in all the phase is same
- BThe shape of $NO_2^ - $ is bent while $NO_3^ - $ is pyramidal
- ✓The hybrid state of $N$ in $NO_3^ - $ and $NO_2^ - $ is same
- DThe hybrid state of $N$ in $NO_2^+$ is $sp^3$
$NO _3{ }^{-}- sp ^2$ hybridized with three bond pairs.
$NO _2^{+}-s p$ hybridised with $2$ bond pairs.
$NO _2{ }^{-}- sp ^2$ hybridized with $2$ bond pairs and one lone pair.
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$\mathrm{C}\mathrm{H}_{3} -\mathrm{C} \equiv \mathrm{CH} \xrightarrow[873\;K]{\text { red hot iron tube}} \mathrm{A}$
the number of sigma$(\sigma)$ bonds present in the product $A$ is
$(I)$ The radius of an anion is larger than that of the parent atom.
$(II)$ The ionization energy generally increases with increasing atomic number in a period.
$(III)$ The electronegativity of an element is the tendency of an isolated atom to attract an electron.
Which of the above statements is/are correct?
[At. nos. $Zn = 30, Sc = 21, $$Ti = 22, Cr = 24$]