Question
Consider two physical quantities A and B related to each other as $E=\frac{B-x^2}{A t}$ where $E, x$ and $t$ have dimensions of energy, length and time respectively. The dimension of $A B$ is
✓
Answer
${[B]=L^2}$
$A=\frac{x^2}{t E}=\frac{L^2}{T^2 T^{-2}}=\frac{1}{M^{-1}}$
${[A]=M^{-1} T}$
${[A B]=\left[L^2 M^{-1} T^1\right]}$
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